-0.02x^2+97x-42000=0

Solution for -0.02x^2+97x-42000=0 equation:

-0.02x^2+97x-42000=0

a = -0.02; b = 97; c = -42000;
Δ = b2-4ac
Δ = 972-4·(-0.02)·(-42000)
Δ = 6049
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(97)-\sqrt{6049}}{2*-0.02}=\frac{-97-\sqrt{6049}}{-0.04}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(97)+\sqrt{6049}}{2*-0.02}=\frac{-97+\sqrt{6049}}{-0.04}
$